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Field of View and Focal Length: The Complete CCTV Lens Guide

Field of view (FOV) is the single most important optical specification for a CCTV camera — it determines the width of the scene at any distance, and therefore every other coverage metric (pixel density, DORI zone boundaries, ANPR plate-read range). This guide derives HFOV and VFOV from first principles using sensor width and focal length, then shows how to solve the inverse problem — "what lens do I need for a given coverage width?"

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1. The HFOV equation

A camera's horizontal field of view is a function of two physical quantities: the width of its image sensor and the focal length of its lens.

HFOV = 2 · arctan( sensor_width / (2 · f) )

where sensor_width is the active width of the image sensor (in mm) and f is the focal length (in mm). The vertical field of view follows from the aspect ratio:

VFOV = 2 · arctan( (sensor_width / AR) / (2 · f) )  where AR = horizontal pixels / vertical pixels

2. Worked example

A 1/2.8" sensor has a width of approximately 5.57 mm. Fit a 4 mm lens:

HFOV = 2 · arctan( 5.57 / (2 · 4) ) = 2 · arctan(0.696) = 2 · 34.86° = 69.7°

At 10 m, this camera sees a horizontal scene width of W = 2 · 10 · tan(34.86°) = 13.9 m. With a 1920 px sensor the pixel density is 1920 / 13.9 = 138 px/m, solidly within the Recognition tier.

Switch to a 2.8 mm lens on the same sensor: HFOV = 2 · arctan(5.57 / 5.6) = 89.5°. At 10 m the scene width jumps to 19.9 m, density drops to 96 px/m — still Observation, but no longer Recognition.

3. Sensor format sizes

FormatWidth (mm)Height (mm)Common in
1/4"3.702.78Very old analogue / specialty
1/3"4.803.60Older HD cameras
1/2.8"5.573.13Standard 1080p–5 MP
1/1.8"7.184.04Higher-end 4K–8K

4. Solving the inverse problem

Given a target coverage width W at distance d, the required HFOV is:

HFOV = 2 · arctan( W / (2 · d) )

Then, given sensor width, solve for focal length:

f = sensor_width / ( 2 · tan(HFOV / 2) )

Example: you need a 20 m wide coverage at 15 m. HFOV = 2 · arctan(20 / 30) = 67.4°. On a 1/2.8" sensor (5.57 mm): f = 5.57 / (2 · tan(33.7°)) = 4.16 mm. The closest standard lens is 4 mm.

Skip the trigonometry. The free CCTV Design Tool does all of this automatically. Pick a camera model, drag it onto the plan, and the exact FOV cone renders at true scale — with no calculations.

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5. Key takeaways for layout engineering

  • Lower focal length = wider view, lower pixel density. A 2.8 mm lens covers a room but may not identify faces at the far end.
  • Higher focal length = narrower view, higher pixel density. A 12 mm lens reads a number plate but misses the scene around it.
  • Sensor size is not negotiable. Two cameras with the same focal length but different sensor formats produce different HFOVs. Always verify the sensor width.
  • Design backwards from the DORI requirement. Establish which tier you need at the farthest point, calculate required HFOV, then select a focal length that delivers it.